JAMB Mathematics Past Questions 2011

10 questions from the JAMB 2011 Mathematics paper, with answers and explanations. Tap "Show answer" under each one when you are ready.

JAMB 2011Question 1 · Algebraic Processes

Make R the subject of the formula if T =

\frac{K R ^{2} + M}{3}

A. $\frac{3 T - K}{M}$
B. $\frac{3 T - M}{K}$
C. $\frac{3 T + K}{M}$
D. $\frac{3 T - K}{M}$

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Answer: B. $\frac{3 T - M}{K}$

Solving T=(KR²+M)/3 for R gives R= $(3 T - M) / K$ .

JAMB 2011Question 2 · Algebraic Processes

25 3 3 x

43 1 2 x

, find the value of x.

A.-6
B.6
C.-12
D.12

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Answer: A. -6

6x-15=8x-3 gives x=-6.

JAMB 2011Question 3 · Calculus

Find the value of x at the minimum point of the curve y = x3 + x2 - x + 1

A. $\frac{1}{3}$
B.- $\frac{1}{3}$
C.1
D.-1

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Answer: A. $\frac{1}{3}$

Critical points x= $\frac{1}{3}$ (minimum) and x=-1 (maximum) from second derivative test.

JAMB 2011Question 4 · Coordinate Geometry and Trigonometry

The midpoint of P(x, y) and Q(8, 6) is (5, 8). Find x and y.

A.(2, 10)
B.(2, 8)
C.(2, 12)
D.(2, 6)

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Answer: A. (2, 10)

x=2, y=10 from midpoint formula.

JAMB 2011Question 5 · Geometry and Mensuration

A chord of circle of radius

7 cm

5 cm

from the centre of the circle.What is the length of the chord?

A.4 $6$ cm
B.3 $6$ cm
C.6 $6$ cm
D.2 $6$ cm

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Answer: A. 4 $6$ cm

Half-chord = $49 - 25$ = $24$ =2 $6$ ; full chord = 4 $6$ cm.

JAMB 2011Question 6 · Inequalities, Permutation, and Combination

Raial has 7 different posters to be hanged in her bedroom, living room and kitchen. Assuming she has plans to place at least a poster in each of the 3 rooms, how many choices does she have?

A.49
B.170
C.21
D.210

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Answer: D. 210

Assigning 3 of 7 distinct posters to 3 distinct rooms: P(7,3) = 210.

JAMB 2011Question 7 · Inequalities, Permutation, and Combination

In how many ways can five people sit round a circular table?

A.24
B.60
C.12
D.120

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Answer: A. 24

Circular arrangement of 5 = (5-1)! = 24.

JAMB 2011Question 8 · Number, Fractions, and Approximation

Simplify

(\frac{16}{81})^{\frac{1}{4}} \div (\frac{9}{16})^{- \frac{1}{2}}

A. $\frac{2}{3}$
B. $\frac{1}{2}$
C. $\frac{8}{9}$
D. $\frac{1}{3}$

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Answer: B. $\frac{1}{2}$

$(\frac{16}{81})^{1/4} = \frac{2}{3}$ and $(\frac{9}{16})^{- 1/2} = \frac{4}{3}$ . Their quotient is $\frac{1}{2}$ .

JAMB 2011Question 9 · Sequences, Series, and Variation

If x varies directly as square root of y and x = 81 when y = 9, Find x when y = 1

\frac{7}{9}

A.20 $\frac{1}{4}$
B.27
C.2 $\frac{1}{4}$
D.36

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Answer: D. 36

x=k $y$ , k=27; at y= $\frac{16}{9}$ , x=27x( $\frac{4}{3}$ )=36.

JAMB 2011Question 10 · Sequences, Series, and Variation

The sum of four consecutive integers is 34. Find the least of these numbers

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Answer: A. 7

4n+6=34 gives n=7, the least number.

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JAMB Mathematics Past Questions 2011

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